Simplify - 22009-22007-22006-22008

The correct option is B 2 2^2009 2^2007/2^2006 2^2008=2^2007(2^2 1)/ (2)^2006(2^2 1) nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbsp; nbs ...

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Properties of Iota

Simplify : ...

Question

Simplify : $\frac{2^{2009} - 2^{2007}}{2^{2006} - 2^{2008}}$

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Solution

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\frac{1}{2} + \frac{2^{1}}{2^{2}} + \frac{2^{2}}{2^{3}} + . . . . . + \frac{2^{2006}}{2^{2007}} + \frac{2^{2007}}{2^{2008}}

2^{2008} - 2^{2007} - 2^{2006} + 2^{2005} = k \cdot 2^{2005}

k

z = {(\frac{\sqrt{3}}{2} + \frac{i}{2})}^{2009} + {(\frac{\sqrt{3}}{2} - \frac{i}{2})}^{2009}

= 3 \times \sqrt{2} \times 4 \sqrt{2} \times 12 \sqrt{32}

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