Question

Simplify: $\frac{21x^4{y}^2}{3x^6{y}^3}$

• A. $\frac{7}{x^{2}y}$
• B. $\frac{7}{xy}$
• C. $\frac{4}{x^{3}y}$
• D. $\frac{7}{x^2{y}^2}$

Answer 1

The correct option is A $\frac{7}{x^{2}y}$

$\frac{21x^4{y}^2}{3x^6{y}^3}=\frac{21}{3}\times \frac{x^4}{x^6}\times \frac{y^2}{y^3}=7\times x^{4-6}\times y^{2-3}=7\times x^{-2}\times y^{-1}=\frac{7}{x^{2}y}$