Question

Simplify :

$\frac{4}{7}\sqrt{147}+\frac{3}{8}\sqrt{192}-\frac{1}{5}\sqrt{75}$ =?

• A. $6\sqrt{3}$
• B. $3\sqrt{3}$
• C. $2\sqrt{3}$
• D. $\sqrt{3}$

Answer 1

Answer: (A)

$6\sqrt{3}$

$\frac{4}{7}\sqrt{147}+\frac{3}{8}\sqrt{192}-\frac{1}{5}\sqrt{75}$
$=\frac{4}{7}\sqrt{3\times 7\times 7}+\frac{3}{8}\sqrt{8\times 8\times 3}-\frac{1}{5}\sqrt{3\times 5\times 5}$
$=\frac{4}{7}\times 7\sqrt{3}+\frac{3}{8}\times 8\sqrt{3}-\frac{1}{5}\times 5\sqrt{3}$
$=4\sqrt{3}+3\sqrt{3}-\sqrt{3}$
$=6\sqrt{3}$.

Therefore, option $A$ is correct.