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B
1
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C
2
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D
3
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Solution
The correct option is C 0 62√3−√6+√6√3+√2−4√3√6−√2 Or 6(2√3+√6)12−6+√6(√3−√2)3−2−4√3(√6+√2)6−2 Or 6(2√3+√6)6+√6(√3−√2)1−4√3(√6+√2)4 Or (2√3+√6)+√6(√3−√2)−√3(√6+√2) Or 2√3+√3√2+√3√2√3−√2√3√2−√3√3√2−√3√2 Or 2√3+√3√2+3√2−2√3−3√2−√3√2=0