Question

Simplify

$\frac{a^2-4b^2}{a^2-9b^2}\times \frac{a-3b}{a+2b}$, then the answer is $\frac{a-2b}{a+3b}$
If true then enter $1$ and if false then enter $0$

Answer 1

Factorizing by using formula $a^2-b^2=(a+b)(a-b)$, we get
$\frac{a^2-4b^2}{a^2-9b^2}\times \frac{a-3b}{a+2b}$,
$=\frac{(a-2b)(a+2b)}{(a-3b)(a+3b)}\times \frac{a-3b}{a+2b}$
$=\frac{a-2b}{a+3b}$