CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Simplify: a2(bc)2(a+c)2b2+b2(ac)2(a+b)2c2+c2(ab)2(b+c)2a2

A
1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
abc
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
a+b+c
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 1
Given, a2(bc)2(a+c)2b2+b2(ac)2(a+b)2c2+c2(ab)2(b+c)2a2

=(a+bc)(ab+c)(a+cb)(a+b+c)+(b+ac)(ba+c)(a+bc)(a+b+c)+(c+ab)(ca+b)(b+ca)(a+b+c)
=(a+bc)(a+b+c)+(ba+c)(a+b+c)+(c+ab)(a+b+c)=(a+bc)+(ba+c)+(ca+b)(a+b+c)
=a+b+c(a+b+c)=1

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Basic Theorems in Differentiation
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon