Question

Simplify: $\frac{{\left(a^3{b}^4\right)}^0{\left(2a^{-2}{b}^2\right)}^0}{2a^0{b}^0\times a{b}^3}$

• A. $\frac{1}{a{b}^3}$
• B. $\frac{1}{2a{b}^3}$
• C. $\frac{1}{a{b}^2}$
• D. $1$

Answer 1

Answer: (B)

$\frac{1}{2a{b}^3}$

$\frac{{\left(a^3{b}^4\right)}^0{\left(2a^{-2}{b}^2\right)}^0}{2a^0{b}^0\times a{b}^3}$
$=\frac{1\times 1}{2\left(1\right)\times a{b}^3}$$(\because x^0=1)$
$=\frac{1}{2\times a{b}^3}$
$=\frac{1}{2a{b}^3}$