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Question

Simplify (xaxb)(a+b).(xbxc)(b+c).(xcxa)(c+a)

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Solution

(xaxb)(a+b).(xbxc)(b+c).(xcxa)(c+a)
=(x(ab))(a+b).(x(bc))(b+c).(x(ca))(c+a)
=xa2b2.xb2c2.xc2a2
=xa2b2+b2c2+c2a2
=x0
=1

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