Simplify i12 -4 3 - ii34 -17 3 - iii9 -3 8 - iv88 - 15 6 - v42 - 11 5 - vi15 -5 6 - vii35 -7 11 - viii28 - 11 4 - ix39 -1312 - x63 - 11 8 -

I) 12÷43 = 12×34=3× 3=9 ii) 34÷173 = 34×317=2× 3=6 iii) 9÷38 = 9×83=3× 8=24 iv) 88÷ 156 = 88×611=8× 6=48 v) 42÷ 115 = 42×56=7× 5=35 vi) ...

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Byju's Answer

Standard VII

Mathematics

Division of Fractions

Simplify i12...

Question

Simplify
$\begin{matrix} i) 12 \div \frac{4}{3} = i i) 34 \div \frac{17}{3} = i i i) 9 \div \frac{3}{8} = i v) 88 \div 1 \frac{5}{6} = v) 42 \div 1 \frac{1}{5} = v i) 15 \div \frac{5}{6} = v i i) 35 \div \frac{7}{11} = v i i i) 28 \div 1 \frac{1}{4} = i x) 39 \div \frac{13}{12} = x) 63 \div 1 \frac{1}{8} = \end{matrix}$

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Solution

i)
$12 \div \frac{4}{3} = 12 \times \frac{3}{4} = 3 \times 3 = 9$

ii)
$34 \div \frac{17}{3} = 34 \times \frac{3}{17} = 2 \times 3 = 6$

iii)
$9 \div \frac{3}{8} = 9 \times \frac{8}{3} = 3 \times 8 = 24$

iv)
$88 \div 1 \frac{5}{6} = 88 \times \frac{6}{11} = 8 \times 6 = 48$

v)
$42 \div 1 \frac{1}{5} = 42 \times \frac{5}{6} = 7 \times 5 = 35$

vi)
$15 \div 1 \frac{5}{6} = 15 \times \frac{6}{5} = 3 \times 6 = 18$

vii)
$35 \div \frac{7}{11} = 35 \times \frac{11}{7} = 5 \times 11 = 55$

viii)
$28 \div 1 \frac{1}{4} = 28 \times \frac{4}{5} = \frac{112}{5}$

ix)
$39 \div \frac{13}{12} = 39 \times \frac{12}{13} = 3 \times 12 = 36$

x)
$63 \div 1 \frac{1}{8} = 63 \times \frac{8}{9} = 7 \times 8 = 56$

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Using power law simplify $(x^{6})^{\frac{3}{2}}$

The remainder obtained when $(2 + 5^{2} + 6^{3} + 11^{4} + 2^{5} + 5^{6} + 6^{7} + 11^{8} + \dots \dots 2^{97} + 5^{98} + 6^{99} + 11^{100})$ is divided by 5 is

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Simplifyi)12÷43=ii)34÷173=iii)9÷38=iv)88÷156=v)42÷115=vi)15÷56=vii)35÷711=viii)28÷114=ix)39÷1312=x)63÷118=

i)12÷43=12×34=3×3=9ii)34÷173=34×317=2×3=6iii)9÷38=9×83=3×8=24iv)88÷156=88×611=8×6=48v)42÷115=42×56=7×5=35vi)15÷156=15×65=3×6=18vii)35÷711=35×117=5×11=55viii)28÷114=28×45=1125ix)39÷1312=39×1213=3×12=36x)63÷118=63×89=7×8=56