Question

Simplify:
$(\frac{1}{2}{)}^{-1}+(\frac{1}{3}{)}^{-1}+(\frac{1}{4}{)}^{-1}$

Answer 1

We have,

${\left(\frac{1}{2}\right)}^{-1}+{\left(\frac{1}{3}\right)}^{-1}+{\left(\frac{1}{4}\right)}^{-1}$

$=\left(\frac{1}{2^{-1}}\right)+\left(\frac{1}{3^{-1}}\right)+\left(\frac{1}{4^{-1}}\right)$

$=2+3+4$

$=9$

Hence, this is the answer.