Question

Simplify $\frac{1}{8}\times 3^{-3}$ and write the answer in exponential form?
(2 marks)

Answer 1

$\frac{1}{8}\times 3^{-3}=\frac{1}{2^3}\times 3^{-3}$

$=2^{-3}\times 3^{-3}(\because \text{For}a\ne 0,\frac{1}{a^m}=a^{-m})$
(1 mark)

$=(2\times 3{)}^{-3}(\because a^m\times b^m=\left(ab{)}^m\right)$
$=6^{-3}$
(1 mark)