The correct option is C (21/40)^4By the Laws of Exponents, we know that a^m × b^m=(ab)^m ⇒ nbsp;(3/8)^4× (7/5)^4=(3×7/8×5)^4=(21/40)^4 ...

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Standard VII

Mathematics

Exponents with Unlike Bases and Same Exponent

Simplify 3/84...

Question

Simplify $(\frac{3}{8})^{4} \times (\frac{7}{5})^{4}$

(\frac{21}{45})^{4}

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(\frac{10}{13})^{4}

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(\frac{21}{40})^{4}

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(\frac{21}{48})^{4}

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Solution

The correct option is C $(\frac{21}{40})^{4}$
By the Laws of Exponents, we know that $a^{m} \times b^{m} = (a b)^{m}$
$\Rightarrow$ $(\frac{3}{8})^{4} \times (\frac{7}{5})^{4} = (\frac{3 \times 7}{8 \times 5})^{4} = (\frac{21}{40})^{4}$

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Similar questions

Question 84 (e)

Simplify and express each of the following in exponential form.
$[{(\frac{3}{5})}^{3} \times {(\frac{3}{5})}^{8}] \div [{(\frac{3}{5})}^{2} \times {(\frac{3}{5})}^{4}]$

Q. Simplify :

5 \sqrt[3]{250} + 7 \sqrt[3]{16} - 14 \sqrt[3]{54}

Question 84 (b)

Simplify $[{(\frac{7}{11})}^{5} \div {(\frac{7}{11})}^{2}] \times {(\frac{7}{11})}^{2}$

Question 84 (x)

Simplify

$(b^{2} - 49) (b + 7) + 343$

Question 84 (x)

Simplify

$(b^{2} - 49) (b + 7) + 343$

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Simplify (38)4×(75)4

The correct option is C (2140)4By the Laws of Exponents, we know that am×bm=(ab)m ⇒ (38)4×(75)4=(3×78×5)4=(2140)4

Simplify $(\frac{3}{8})^{4} \times (\frac{7}{5})^{4}$

The correct option is C $(\frac{21}{40})^{4}$
By the Laws of Exponents, we know that $a^{m} \times b^{m} = (a b)^{m}$
$\Rightarrow$ $(\frac{3}{8})^{4} \times (\frac{7}{5})^{4} = (\frac{3 \times 7}{8 \times 5})^{4} = (\frac{21}{40})^{4}$