Question

Simplify:

$\frac{5}{7}-\frac{1}{14}-\frac{3}{28}$

Answer 1

Given, $\frac{5}{7}-\frac{1}{14}-\frac{3}{28}$

Consider the denominator of $\frac{5}{7}-\frac{1}{14}-\frac{3}{28}$ i.e., $7,14,28$

The LCM of $7,14,28$ is $28$

Now the fraction becomes

$$\begin{gathered} \Rightarrow \frac{{\displaystyle \frac{5}{7}}\times 28-{\displaystyle \frac{1}{14}}\times 28-{\displaystyle \frac{3}{28}}\times 28}{28} \\ \Rightarrow \frac{5\times 4-1\times 2-3\times 1}{28} \\ \Rightarrow \frac{20-2-3}{28} \\ =\frac{15}{28} \end{gathered}$$

Hence, the required fraction is $\frac{15}{28}$.