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Question

Simplify:
a3275a216a+3÷a2+3a+925a21

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Solution

a3275a216a+3÷a2+3a+925a21
{AB÷CD=AB×DC}
a3275a216a+3×25a21a3+3a+9
{A3B3=(AB)(A2+B2+AB),A2B2=(AB)(A+B)}
(a3)(a2+3a+a)(5a1)(a3)×(5a1)(5a+1)(a2+4a+a)
5a+1.

1190326_1242060_ans_fd17112e130e4bda9403acc51a6deeaf.jpg

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