Simplify: a−4 × b3 × c5 × d−7a−7 × b−3 × c2 × d−9
a3b6c3d2
a3b5c3d2
a2b6c3d2
a3b6c3d4
Using the fact that knkm=kn−m for k≠0, a−4 × b3 × c5 × d−7a−7 × b−3 × c2 × d−9
=a(−4+7)×b(3+3)×c(5−2)×d(−7+9)
=a3×b6×c3×d2
=a3b6c3d2
If A = {1, 2, 3, 4}
B = {3, 4, 5, 6, 7}
C = {6, 7, 8, 9}
D = {7, 8, 9, 10}
ColumnAColumnB1.A∪B a. {3,4,6,7} 2.A∩B b. ∅ 3.(B∩C)∪D c. {3,4} 4. B∪C∪D d. {3,4,5,6,7,8,9,10} 5. (A∩B)∩(B∪C) e. {1,2,3,4,5,6,7} f. {6,7,8,9,10} g. {7}