The correct option is D 2√(32) + √(48)/√(8) + √(12)=√(16 × 2) + √(16 × 3)/√(4 × 2) + √(4 × 3) 4√(2) + 4√(3)/2√(2)+2√(3) = 4(√(2)+√(3))/2(√(2)+√(3)) =2 ...

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Byju's Answer

Standard VIII

Mathematics

Finding Square Root through Prime Factorisation

Simplify√32+√...

Question

Simplify
$\frac{\sqrt{32} + \sqrt{48}}{\sqrt{8} + \sqrt{12}} = ?$

\sqrt{2}

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Solution

The correct option is B $2$
$\frac{\sqrt{32} + \sqrt{48}}{\sqrt{8} + \sqrt{12}} = \frac{\sqrt{16 \times 2} + \sqrt{16 \times 3}}{\sqrt{4 \times 2} + \sqrt{4 \times 3}}$
$\frac{4 \sqrt{2} + 4 \sqrt{3}}{2 \sqrt{2} + 2 \sqrt{3}} = \frac{4 (\sqrt{2} + \sqrt{3})}{2 (\sqrt{2} + \sqrt{3})}$
$= 2$

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Similar questions

Q. Simplify :

\frac{\sqrt{32} + \sqrt{48}}{\sqrt{8} + \sqrt{12}}

Simplify √32 +√48 ÷√8+√12.can we solve this by taking 32raised to 1/2+48 raised to 1/2 ?can we??

Q. Simplify:

4 \sqrt{3} (2 \sqrt{27} - 4 \sqrt{48}) - 5 \sqrt{3} (\sqrt{12} - 3 \sqrt{75})

$\frac{\sqrt{32} + \sqrt{48}}{(\sqrt{8} + \sqrt{12})} = ?$

Q. Evaluate:

\frac{\sqrt{32} + \sqrt{48}}{\sqrt{8} + \sqrt{12}}

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Simplify √32+√48√8+√12=?

The correct option is B 2√32+√48√8+√12=√16×2+√16×3√4×2+√4×3 4√2+4√32√2+2√3=4(√2+√3)2(√2+√3) =2

Simplify
$\frac{\sqrt{32} + \sqrt{48}}{\sqrt{8} + \sqrt{12}} = ?$

The correct option is B $2$
$\frac{\sqrt{32} + \sqrt{48}}{\sqrt{8} + \sqrt{12}} = \frac{\sqrt{16 \times 2} + \sqrt{16 \times 3}}{\sqrt{4 \times 2} + \sqrt{4 \times 3}}$
$\frac{4 \sqrt{2} + 4 \sqrt{3}}{2 \sqrt{2} + 2 \sqrt{3}} = \frac{4 (\sqrt{2} + \sqrt{3})}{2 (\sqrt{2} + \sqrt{3})}$
$= 2$