Question

Simplify
$\frac{x^2-3x+2}{x^2-1}$ as a ratio of 2 linears

Answer 1

We have,

$\frac{x^2-3x+2}{x^2-1}$

$=\frac{x^2-(2+1)x+2}{x^2-1^2}$

$=\frac{x^2-2x-1x+2}{(x+1)(x-1)}$

$=\frac{x(x-2)-1(x-2)}{(x+1)(x-1)}$

$=\frac{(x-2)(x-1)}{(x+1)(x-1)}$

$=\frac{(x-2)}{(x+1)}$

Hence, this is the answer.