wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Simplify xx2+3x−4+4xx2+7x+12.

A
x(5x1)(x1)(x+3)(x+4)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x(5x+1)(x1)(x+3)(x+4)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x(5x1)(x+1)(x+3)(x+4)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x(5x+1)(x+1)(x+3)(x+4)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A x(5x1)(x1)(x+3)(x+4)
xx2+3x4+4xx2+7x+12=x(x1)(x+4)+4x(x+3)(x+4)

L.C.D=(x1)(x+3)(x+4)

=x(x+3)+4x(x1)(x1)(x+3)(x+4)

=5x2x(x1)(x+3)(x+4)

=x(5x1)(x1)(x+3)(x+4)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Adaptive Q28
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon