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Question

Simplify xx2+3x−4+4xx2+7x+12.

A
x(5x1)(x1)(x+3)(x+4)
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B
x(5x+1)(x1)(x+3)(x+4)
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C
x(5x1)(x+1)(x+3)(x+4)
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D
x(5x+1)(x+1)(x+3)(x+4)
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Solution

The correct option is A x(5x1)(x1)(x+3)(x+4)
xx2+3x4+4xx2+7x+12=x(x1)(x+4)+4x(x+3)(x+4)

L.C.D=(x1)(x+3)(x+4)

=x(x+3)+4x(x1)(x1)(x+3)(x+4)

=5x2x(x1)(x+3)(x+4)

=x(5x1)(x1)(x+3)(x+4)

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