Question

Simplify ,giving solution with positive index
$x^2{y}^3.6x^{5}y.9x^3{y}^4$

Answer 1

Step:simplifying using laws of exponents

Given,$x^2{y}^3.6x^{5}y.9x^3{y}^4$
It can be written as:
$6\times 9\times x^{2+5+3}\times y^{3+1+4}$ [$\because a^m\times a^n=a^{m+n}$]
On further calculation ,we have
$x^2{y}^3.6x^{5}y.9x^3{y}^4$
$=54x^{10}{y}^8$

Hence, $x^2{y}^3.6x^{5}y.9x^3{y}^4=54x^{10}{y}^8$.