Simplify ,giving solution with positive index
$x^{2} y^{3} .6 x^{5} y .9 x^{3} y^{4}$

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Solution

Step:simplifying using laws of exponents

Given, $x^{2} y^{3} .6 x^{5} y .9 x^{3} y^{4}$
It can be written as:
$6 \times 9 \times x^{2 + 5 + 3} \times y^{3 + 1 + 4}$ [ $∵ a^{m} \times a^{n} = a^{m + n}$ ]
On further calculation ,we have
$x^{2} y^{3} .6 x^{5} y .9 x^{3} y^{4}$
$= 54 x^{10} y^{8}$

Hence, $x^{2} y^{3} .6 x^{5} y .9 x^{3} y^{4} = 54 x^{10} y^{8}$ .

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