Question

Simplify, giving solution with positive index​ (xvi) $(-2^2)\times (0{)}^3\times (3^3)$.

Answer 1

Given , $(-2^2)\times (0{)}^3\times (3^3)$.
It can be written as:

$(-2^2)\times (0{)}^3\times (3^3)$ =(-2)\times (-2)\times (0)\times (0)\times (0)\times (3)\times (3)\times (3)\)

$=4\times 0\times 27$

On further calculation , we have:

$(-2^2)\times (0{)}^3\times (3^3)=0$

Hence, $(-2^2)\times (0{)}^3\times (3^3)=0$.