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Byju's Answer
Standard VI
Mathematics
Subtraction of Integers
Simplify:i -3...
Question
Simplify:
(i)
-
3
2
+
5
4
-
7
4
(ii)
5
3
-
7
6
+
-
2
3
(iii)
5
4
-
7
6
-
-
2
3
(iv)
-
2
5
-
-
3
10
-
-
4
7
(v)
5
6
+
-
2
5
-
-
2
15
(vi)
3
8
-
-
2
9
+
-
5
36
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Solution
(
i
)
-
3
2
+
5
4
-
7
4
Taking
t
h
e
L
.
C
.
M
.
of
the
denominators
:
-
6
4
+
5
4
-
7
4
=
-
6
+
5
-
7
4
=
-
8
4
=
-
2
(
ii
)
5
3
-
7
6
+
-
2
3
Taking
t
h
e
L
.
C
.
M
.
of
the
denominators
:
10
6
-
7
6
+
-
4
6
=
10
-
7
+
(
-
4
)
6
=
10
-
7
-
4
6
=
-
1
6
(
iii
)
5
4
-
7
6
-
-
2
3
Taking
t
h
e
L
.
C
.
M
.
of
the
denominators
:
15
12
-
14
12
-
-
8
12
=
15
-
14
-
(
-
8
)
12
=
15
-
14
+
8
12
=
9
12
=
3
4
(
iv
)
-
2
5
-
-
3
10
-
-
4
7
Taking
t
h
e
L
.
C
.
M
.
of
the
denominators
:
-
28
70
-
-
21
70
-
-
40
70
=
(
-
28
)
-
(
-
21
)
-
(
-
40
)
70
=
-
28
+
21
+
40
70
=
33
70
(
v
)
5
6
+
-
2
5
-
-
2
15
Taking
t
h
e
L
.
C
.
M
.
of
the
denominators
:
25
30
+
-
12
30
-
-
4
30
=
25
+
(
-
12
)
-
(
-
4
)
30
=
25
-
12
+
4
30
=
17
30
(
vi
)
3
8
-
-
2
9
+
-
5
36
Taking
t
h
e
L
.
C
.
M
.
of
the
denominators
:
27
72
-
-
16
72
+
-
10
72
=
27
-
(
-
16
)
+
(
-
10
)
72
=
27
+
16
-
10
72
=
33
72
=
11
24
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0
Similar questions
Q.
Simplify:
(i)
-
3
2
+
5
4
-
7
4
(ii)
5
3
-
7
6
+
-
2
3
(iii)
5
4
-
7
6
-
-
2
3
(iv)
-
2
5
-
-
3
10
-
-
4
7
Q.
Evaluate:
(i) 15 + (−8)
(ii) (−16) + 9
(iii) (−7) + (−23)
(iv) (−32) + 47
(v) 53 + (−26)
(vi) (−48) + (−36)
Q.
If
25
k
=
1
2
−
2
2
5
2
+
2
3
5
3
−
4
2
5
4
+
2
5
5
5
−
2
6
5
6
+
.
.
.
.
.
∞
then find the value of
k
Q.
Evalute:
sin
2
θ
+
sin
2
(
90
−
θ
)
3
(
sec
2
61
∘
−
cot
2
29
∘
)
−
3
cot
2
30
∘
sin
2
54
∘
sec
2
36
∘
2
(
cos
e
c
2
65
∘
−
tan
2
25
∘
)
Q.
Prove that
(i)
8
-
2
3
×
2
1
2
×
25
-
5
4
÷
32
-
2
5
×
125
-
5
6
=
2
(ii)
64
125
-
2
3
+
1
256
625
1
4
+
25
64
3
=
65
16
(iii)
7
81
1
4
+
256
1
4
1
4
4
=
16807
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