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Byju's Answer
Standard IX
Mathematics
Conditional Identities
Simplify:i 4+...
Question
Simplify:
(i)
4
+
2
4
-
2
(ii)
5
+
3
5
-
3
(iii)
6
-
6
6
+
6
(iv)
5
-
2
2
-
3
(v)
5
-
3
2
(vi)
3
-
3
2
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Solution
(
i
)
4
+
2
4
-
2
=
4
2
-
2
2
[
a
+
b
a
-
b
=
a
2
-
b
2
]
=
16
-
2
=
14
(
ii
)
5
+
3
5
-
3
=
5
2
-
3
2
=
5
-
3
=
2
(
iii
)
6
-
6
6
+
6
=
6
2
-
6
2
=
36
-
6
=
30
(
iv
)
5
-
2
2
-
3
=
5
×
2
-
5
×
3
-
2
×
2
+
2
×
3
=
10
-
15
-
2
+
6
(
v
)
5
-
3
2
=
5
2
+
3
2
-
2
×
5
3
[
a
-
b
2
=
a
2
+
b
2
-
2
a
b
]
=
5
+
3
-
2
15
=
8
-
2
15
(
vi
)
3
-
3
2
=
3
2
+
3
2
-
2
×
3
×
3
[
a
-
b
2
=
a
2
+
b
2
-
2
a
b
]
=
9
+
3
-
6
3
=
12
-
6
3
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Similar questions
Q.
Simplify:
(i)
3
2
-
2
3
3
2
+
2
3
+
12
3
-
2
(ii)
5
+
3
5
-
3
+
5
-
3
5
+
3
(iii)
7
+
3
5
3
+
5
+
7
-
3
5
3
-
5
(iv)
1
2
+
3
+
2
5
-
3
+
1
2
-
5
(v)
2
5
+
3
+
1
3
+
2
+
3
5
+
2