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Question

Simplify:
(i) 47÷914
(ii) 710÷35
(iii) 89÷16
(iv) 9÷13=9×3
(v) 24÷67=24×76
(vi) 335÷45
(vii) 337÷821
(viii) 547÷1310
(ix) 1537÷12349

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Solution

(i) 47÷914=47×149 [Since, Reciprocal of 914=149]
=89
(ii) 710÷35=710×53 [Since, Reciprocal of 35=53]
=76
(iii) 89÷16=89×116 [Since, Reciprocal of 16=116]
=118
(iv) 9÷13=9×3 [Since, Reciprocal of 13=3]
=27
(v) 24÷67=24×76 [Since, Reciprocal of 67=76]
=4×7=28
(vi) 335÷45=185÷45
=185×54 [Since, Reciprocal of 45=54]
=184
=92=412
(vii) 337÷821=247÷821
=247×218
[Since, Reciprocal of 821=218]
=3×3
=9
(viii) 547÷1310=397÷1310
=397×1013 [Since, Reciprocal of 1310=1013]
=307
=427
(ix) 1537÷12349=1087÷7249
=1087×4972
[ Reciprocal of 7249=4972]
=9×71×6
=3×71×2
=212=1012


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