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Question

Simplify (i) (3x+4)3(3x4)3 (ii) (x+2x)3+(x2x)3

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Solution

(i) (3x+4)3(3x4)3
=[(3x)3+(4)3+3(3x)(4)(3x+4)][(3x)2(4)33(3x)(4)(3x4)]
=[27x3+64+36x(3x+4)][27x36436x(3x4)]
=[27x3+64+108x2+144x][27x364108x2+144x]
=27x3+64+108x2+144x27x3+64+108x2144x
=128+2162
(ii) (x+2x)3+(x2x)3
=x3+(2x)3+3(x)(2x)(x+2x)+x3(2x)33(x)(2x)(x2x)
=x3+8x3+6x+12x+x38x36x+12x=2x3+24x

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