Question

Simplify:

(ii) $3+\frac{5}{-7}$

Answer 1

To find: $3+\frac{5}{-7}$

$\therefore 3+\frac{5}{-7}=\frac{3}{1}+\frac{-5}{7}$
LCM of denominators $1$ and $7=7$
$\Rightarrow 3+\frac{5}{-7}=\frac{3}{1}+\frac{-5}{7}$
$=\frac{3\times 7}{1\times 7}+\frac{-5}{7}$
$=\frac{21}{7}+\frac{-5}{7}$
$=\frac{21+(-5)}{7}$
$=\frac{16}{7}$

Hence $3+\frac{5}{-7}=\frac{16}{7}$