Question

simplify in exponent form:

$36a^4{b}^6{c}^3\sqrt[6]{6108}$

Answer 1

$36a^4{b}^6{c}^3\sqrt[6]{6108}=2^2\times 3^2\times (2^2\times 3^3{)}^{1/6}{a}^4{b}^6{c}^3=2^{2+\frac{1}{3}}\times 3^{2+\frac{1}{2}}\times a^4{b}^6{c}^3=2^{7/3}\cdot 3^{5/2}\cdot a^4{b}^6{c}^3$