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Question

Simplify:
(1+x2y2z22yz)(1x+yz+1z+xy)

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Solution

Now,
(1+x2+y2+z22yz)(1x+y+z+1z+xy)
=(x2(y22yz+z2)2yz)(z+xy+x+yz(x+yz)(z+xy))
=x2(yz)22yz,2x(x+yz)(z+xy)
=(xy+z)(x+yz)2yz,2x(x+yz)(z+xy)
=(2x2yz)=(xyz)


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