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Byju's Answer
Standard VIII
Mathematics
Algebraic Identities
Simplify 10...
Question
Simplify
(
101
)
2
using suitable identity.
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Solution
101
2
=
(
100
+
1
)
2
is of the form
(
a
+
b
)
2
where
a
=
100
,
b
=
1
We know
(
a
+
b
)
2
=
a
2
+
b
2
+
2
a
b
∴
(
100
+
1
)
2
=
100
2
+
1
2
+
2
×
100
×
1
=
10000
+
1
+
200
=
10201
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