Question

Simplify: $\left[12\left(104-2\right)+36\times 2\right]÷\left[13\left(10+2\right)-12\right]$

Answer 1

We have to use BODMAS Rule in this question.

BODMAS stands for Brackets, Of, Division, Multiplication, Addition, Subtraction

First we open brackets, in brackets order will be , BAR,PARENTHESES, CURLY BRACKETS, SQUARE BRACKETS

$$\begin{gathered} \left[12\left(104-2\right)+36\times 2\right]÷\left[13\left(10+2\right)-12\right] \\ =\left[12\times 102+36\times 2\right]÷\left[13\times 12-12\right]\left[\mathrm{Opening}\mathrm{Parentheses}\right] \\ =\left[1224+72\right]÷\left[156-12\right] \\ =1296÷144\left[\mathrm{Opening}\mathrm{Square}\mathrm{bracket}\right] \\ =9 \end{gathered}$$

Hence, the answer is $9$