Question

Simplify:
$\left(2^{-1}\times 4^{-1}\right)÷2^{-2}$

Answer 1

We have,

$(2^{-1}\times 4^{-1})÷2^{-2}$

$=(\frac{1}{2}\times \frac{1}{4})÷\frac{1}{2^2}$

$=\left(\frac{1}{8}\right)÷\frac{1}{4}$

$=\frac{\frac{1}{8}}{\frac{1}{4}}$

$=\frac{4}{8}$

$=\frac{1}{2}$

Hence, this is the answer.