Question

Simplify:
${\left(27x^3\right)}^{\frac{1}{3}}\times {\left(81y^3\right)}^{\frac{1}{3}}$

Answer 1

$(27x^3{)}^{\frac{1}{3}}\times (81y^3{)}^{\frac{1}{3}}$

$=\left(\right(3x{)}^3{)}^{\frac{1}{3}}\times (3^4{)}^{\frac{1}{3}}\times (y^3{)}^{\frac{1}{3}}$

$=3x\times 3^1.\sqrt[3]{33}\times y$

$=3^{\frac{7}{3}}xy$