Question

Simplify:
$(4^{-1}\times 3^{-1})÷6^{-1}$

• A. $\frac{1}{2}$
• B. $\frac{1}{4}$
• C. $\frac{2}{2}$
• D. None of these

Answer 1

The correct option is A $\frac{1}{2}$

we know,

$a^m\ast b^m=(ab{)}^m$

so,

$4^{-1}\ast 3^{-1}={12}^{-1}$

we know,

$\frac{a^{-m}}{b^{-m}}=(\frac{a}{b}{)}^{-m}=(\frac{b}{a}{)}^m$

so,

$\frac{{12}^{-1}}{6^{-1}}=2^{-1}=\frac{1}{2}$