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Byju's Answer
Standard IX
Mathematics
Laws of Exponents for Real Numbers
Simplify : ...
Question
Simplify :
[
5
(
8
1
3
+
27
1
3
)
3
]
1
4
Open in App
Solution
=
[
5
(
8
1
/
3
+
27
1
/
3
)
3
]
1
/
4
=
[
5
(
2
3
×
1
/
3
+
3
3
×
1
/
3
)
3
]
1
/
4
=
[
5
(
2
+
3
)
3
]
1
/
4
=
(
5.5
3
)
1
/
4
=
(
5
4
)
1
/
4
f
=
5
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23
Similar questions
Q.
Evaluate:
[
5
(
8
1
3
+
27
1
3
)
3
]
1
4
Q.
Simplify:
(
5
(
8
1
/
3
+
27
1
/
3
)
3
)
1
/
4
Q.
Fill in the blanks
(
5
(
8
1
/
3
+
27
1
/
3
)
3
)
1
/
4
=
_____.
Q.
Find the value of the following
a
)
[
5
(
8
1
3
+
27
1
3
)
3
]
1
4
b
)
(
0.000064
)
5
4
×
(
0.04
)
5
4
[4 MARKS]
Q.
Simplify:
(i)
(
27
)
4
3
+
(
32
)
0.8
+
(
0.8
)
−
1
(ii)
(
64
125
)
−
2
3
÷
1
(
256
625
)
1
4
×
√
25
3
√
64
(iii)
⎡
⎢ ⎢
⎣
5
⎛
⎜
⎝
8
1
3
+
27
1
3
⎞
⎟
⎠
3
⎤
⎥ ⎥
⎦
1
4
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