You visited us 1 times! Enjoying our articles? Unlock Full Access!

Addition and Subtraction of Algebraic Expression

Simplify: 5...

Question

Simplify: $(5 x^{2} - 3 x + 2) - ({3 x}^{2} + 5 x - 1) + (6 x^{2} - 2)$

5 x^{2} - 3 x + 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6 x^{2} - 4 x + 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 x^{2} - 8 x + 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

8 x^{2} - 9 x + 5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $8 x^{2} - 8 x + 1$
The value of
$(5 x^{2} - 3 x + 2) - (3 x^{2} + 5 x - 1) + (6 x^{2} - 2)$
$= (5 x^{2} - 3 x^{2} + 6 x^{2}) + (- 3 x - 5 x) + (2 + 1 - 2)$
$= 8 x^{2} - 8 x + 1$

Suggest Corrections

Similar questions

\frac{6 x^{2} + 13 x - 5}{9 x^{2} + 3 x - 2} \times \frac{3 x^{2} - 10 x - 8}{16 x^{2} - 1} .

\frac{5 x + 20}{7 x + 28}

\frac{x^{3} - 5 x^{2}}{3 x^{3} + 2 x^{4}}

\frac{6 x^{2} - 5 x + 1}{9 x^{2} + 12 x - 5}

\frac{(x - 3) (x^{2} - 5 x + 4)}{(x - 1) (x^{2} - 2 x - 3)}

If $α, β$ are the roots of the equation $2 x^{2} + 5 x + 6 = 0$ , then find the equation whose roots are $\frac{1}{α} a n d \frac{1}{β}$ .

8 x^{2} + 2 x - 3 = 0

- 2 x^{2} + 3 x + 2 = 0

5 x^{2} - 2 x - 10 = 0

\frac{1}{2 x - 3} + \frac{1}{x - 5} = 1, x \neq \frac{3}{2}, 5

x^{2} + 5 \sqrt{5} x - 70 = 0

Join BYJU'S Learning Program