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Byju's Answer
Standard VIII
Mathematics
Powers with Negative Exponents
Simplify: ...
Question
Simplify:
⎛
⎜ ⎜
⎝
b
−
3
.
b
7
.
(
b
−
1
)
2
(
b
)
2
.
(
b
2
)
3
⎞
⎟ ⎟
⎠
−
2
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Solution
⎛
⎜ ⎜
⎝
b
−
3
.
b
7
.
(
b
−
1
)
2
(
−
b
)
2
.
(
b
2
)
3
⎞
⎟ ⎟
⎠
−
2
=
⎛
⎜ ⎜
⎝
b
(
7
−
3
)
.
(
b
−
2
)
(
b
)
2
.
(
b
6
)
⎞
⎟ ⎟
⎠
−
2
.... [Using product and power rules of exponents]
=
(
b
4
−
2
b
6
+
2
)
−
2
...... [Using product rule of exponents]
=
(
b
2
b
8
)
−
2
=
(
b
(
2
−
8
)
)
−
2
...... [Using quotient rule of exponents]
=
(
b
−
6
)
(
−
2
)
=
b
12
....... [Using product rule of exponents]
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Similar questions
Q.
(
b
−
3
⋅
b
7
⋅
(
b
−
1
)
2
(
−
b
)
2
⋅
(
b
2
)
3
)
−
2
.
Q.
Simplify:
(
a
2
−
b
2
)
3
+
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3
+
(
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Q.
The value of
3
[
(
a
2
−
b
2
)
3
+
(
b
2
−
c
2
)
3
+
(
c
2
−
1
2
)
3
(
a
−
b
)
3
+
(
b
−
c
)
3
+
(
c
−
a
)
3
]
= ?
Q.
Find
(
a
2
−
b
2
)
3
+
(
b
2
−
c
2
)
3
+
(
c
2
−
a
2
)
3
(
a
−
b
)
3
+
(
b
−
c
)
3
+
(
c
−
a
)
3
=
Q.
Simplify:
(
−
10
a
3
b
+
12
a
2
b
2
−
6
a
b
3
)
−
(
8
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+
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b
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b
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