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Question

Simplify: ⎜ ⎜b3.b7.(b1)2(b)2.(b2)3⎟ ⎟2

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Solution

⎜ ⎜b3.b7.(b1)2(b)2.(b2)3⎟ ⎟2
=⎜ ⎜b(73).(b2)(b)2.(b6)⎟ ⎟2 .... [Using product and power rules of exponents]
=(b42b6+2)2 ...... [Using product rule of exponents]
=(b2b8)2
=(b(28))2 ...... [Using quotient rule of exponents]
=(b6)(2)
=b12 ....... [Using product rule of exponents]

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