Question

Simplify:
${\left(\frac{27}{125}\right)}^{-1}=$

• A. $\frac{3}{5}$
• B. ${\left(\frac{3}{5}\right)}^{-1}$
• C. ${\left(\frac{3}{5}\right)}^{-2}$
• D. ${\left(\frac{5}{3}\right)}^3$

Answer 1

The correct option is D ${\left(\frac{5}{3}\right)}^3$

${\left(\frac{125}{27}\right)}^1$ using $\frac{1}{a^m}=a^{-m}$

$=\frac{5^3}{3^3}$

$={\left(\frac{5}{3}\right)}^3$