Simplify: ${(\frac{32}{243})}^{- \frac{1}{5}}$ .

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Solution

$(32 / 243)^{- 1 / 5}$
$(2^{5} / 3^{5})^{- 1 / 5}$
$(\frac{2}{3})^{5 \times \frac{- 1}{5}}$
$(\frac{2}{3})^{- 1}$
$= \frac{3}{2}$

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