Question

Simplify:
${\left(\frac{-4}{3}\right)}^8÷{\left(\frac{-4}{3}\right)}^{12}$

Answer 1

Now,

${\left(\frac{-4}{3}\right)}^8÷{\left(\frac{-4}{3}\right)}^{12}$

$=\frac{{\left(\frac{-4}{3}\right)}^8}{{\left(\frac{-4}{3}\right)}^{12}}$

$={\left(\frac{-4}{3}\right)}^{8-12}$

$={\left(\frac{-4}{3}\right)}^{-4}$

$=\frac{3^4}{4^4}$

$=\frac{81}{256}$.