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Question

Simplify:
(xaxb)a2+ab+b2×(xbxc)b2+bc+c2×(xcxa)c2+ca+a2

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Solution

(xaxb)a2+ab+b2×(xbxc)b2+bc+c2×(xcxa)c2+ca+a2
=(xab)a2+ab+b2×(xbc)b2+bc+c2×(xca)c2+ca+a2
=xa3b3×xb3c3×xc3a3
xa3b3+b3c3+c3a3
x0
=1

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