Question

Simplify:
${\left(\frac{x^b}{x^c}\right)}^a$$\times {\left(\frac{x^c}{x^a}\right)}^b$$\times {\left(\frac{x^a}{x^b}\right)}^c$

Answer 1

Now,

${\left(\frac{x^b}{x^c}\right)}^a$$\times {\left(\frac{x^c}{x^a}\right)}^b$$\times {\left(\frac{x^a}{x^b}\right)}^c$

$=(x^{b-c}{)}^a\times (x^{c-a}{)}^b\times (x^{a-b}{)}^c$

$=x^{(ab-ac+bc-ab+ac-bc)}$

$=x^0$

$=1$.