Simplify 78-7417-79-71019-710-7818

The correct option is D 1 (7^8/7^9)^17×(7^9/7^10)^19×(7^10/7^8)^18 =7^ 17× 7^ 19× 7^36=7^0 =7^0=1 ...

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Byju's Answer

Standard VIII

Mathematics

Expansion of (x-y)^3

Simplify 78/7...

Question

Simplify ${(\frac{7^{8}}{7^{9}})}^{17} \times {(\frac{7^{9}}{7^{10}})}^{19} \times {(\frac{7^{10}}{7^{8}})}^{18}$

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Solution

The correct option is D
1

${(\frac{7^{8}}{7^{9}})}^{17} \times {(\frac{7^{9}}{7^{10}})}^{19} \times {(\frac{7^{10}}{7^{8}})}^{18}$
$= 7^{- 17} \times 7^{- 19} \times 7^{36} = 7^{0}$
$= 7^{0} = 1$

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Similar questions

Simplify ${(\frac{7^{8}}{7^{9}})}^{17} \times {(\frac{7^{9}}{7^{10}})}^{19} \times {(\frac{7^{10}}{7^{8}})}^{18}$

Q. Simplify:

(1)

\frac{5}{9} + \frac{8}{9}

(2)

\frac{13}{8} - \frac{7}{8}

(3)

\frac{4}{5} + \frac{- 7}{10}

(4)

\frac{- 10}{7} - \frac{1}{2}

(5)

\frac{- 13}{4} + \frac{- 3}{4}

(6)

\frac{- 13}{4} - \frac{- 3}{4}

(7)

\frac{2}{5} - \frac{7}{9}

(8)

\frac{- 3}{5} + \frac{2}{7}

Simplify each of the following and write as a rational number of the form $\frac{p}{q}$ :
(i) $\frac{3}{4} + \frac{5}{6} + \frac{- 7}{8}$
(ii) $\frac{2}{3} + \frac{- 5}{6} + \frac{- 7}{9}$
(iii) $\frac{- 11}{2} + \frac{7}{6} + \frac{- 5}{8}$
(iv) $\frac{- 4}{5} + \frac{- 7}{10} + \frac{- 8}{15}$
(v) $\frac{- 9}{10} + \frac{22}{15} + \frac{13}{- 20}$
(vi) $\frac{5}{3} + \frac{3}{- 2} + \frac{- 7}{3} + 3$

Q. Simplify:

5 \frac{1}{7} - \{3 \frac{3}{10} \div (2 \frac{4}{5} - \frac{7}{10})\}

Q. Simplify:

\frac{(2^{2}) \times 7^{10}}{3^{2} \times 7}

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Simplify (7879)17×(79710)19×(71078)18

The correct option is D 1 (7879)17×(79710)19×(71078)18 =7−17×7−19×736=70 =70=1

Simplify ${(\frac{7^{8}}{7^{9}})}^{17} \times {(\frac{7^{9}}{7^{10}})}^{19} \times {(\frac{7^{10}}{7^{8}})}^{18}$

The correct option is D
1

${(\frac{7^{8}}{7^{9}})}^{17} \times {(\frac{7^{9}}{7^{10}})}^{19} \times {(\frac{7^{10}}{7^{8}})}^{18}$
$= 7^{- 17} \times 7^{- 19} \times 7^{36} = 7^{0}$
$= 7^{0} = 1$