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Question

Simplify: apqqaq2pq×a2(qp)n

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Solution

{apqqaq2pq×a2(qp)}n =⎪ ⎪⎪ ⎪a(pq+2q2p)aq2pqq⎪ ⎪⎪ ⎪n
={a(qp)a(qp)}n
=1

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