Simplify- - 1 2 -3 - 1 3 -3 - 1 4 -3 - - 3 2

[ (1/2)^ 3 + (1/3)^ 3 + (1/4)^ 3] ÷(3)^2 =[(2)^3+(3)^3+(4)^3] ÷ 9 =998=11 ...

You visited us 2 times! Enjoying our articles? Unlock Full Access!

Simplification of an Expression

Simplify: [ ...

Question

Simplify:
$[{(\frac{1}{2})}^{- 3} + {(\frac{1}{3})}^{- 3} + {(\frac{1}{4})}^{- 3}] \div {(3)}^{2}$

Open in App

Solution

Suggest Corrections

Similar questions

{[{(\frac{2}{3})}^{2}]}^{3} \times {(\frac{2}{3})}^{- 4} \times 3^{- 1} \times \frac{1}{6}

{[{(\frac{2}{3})}^{2}]}^{3} \times {(\frac{1}{3})}^{- 2} \times 3^{- 1} \times \frac{1}{6}

{(81)}^{\frac{3}{4}} - {(\frac{1}{32})}^{\frac{- 2}{5}} + 8^{\frac{1}{3}} {(\frac{1}{2})}^{- 1}

\frac{4 + \sqrt{5}}{4 - \sqrt{5}} + \frac{4 - \sqrt{5}}{4 + \sqrt{5}}

\frac{1}{\sqrt{3} + \sqrt{2}} - \frac{2}{\sqrt{5} - \sqrt{3}} - \frac{3}{\sqrt{2} - \sqrt{5}}

\frac{2 + \sqrt{3}}{2 - \sqrt{3}} + \frac{2 - \sqrt{3}}{2 + \sqrt{3}} + \frac{\sqrt{3} - 1}{\sqrt{3} + 1}

\frac{2 \sqrt{6}}{\sqrt{2} + \sqrt{3}} + \frac{6 \sqrt{2}}{\sqrt{6} + \sqrt{3}} - \frac{8 \sqrt{3}}{\sqrt{6} + \sqrt{2}}

(\frac{1}{3})^{2} \times 3^{- 2}

Join BYJU'S Learning Program