Simplify: ${(x^{3 n + 1} . x^{3 n - 1})}^{2}$

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Solution

given, ${(x^{3 n + 1} . x^{3 n - 1})}^{2}$

$= {(x^{3 n + 1 + 3 n - 1})}^{2}$

$= {(x^{6 n})}^{2}$

$= x^{12 n}$

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