Simplify ${log}_{8} 128 - {log}_{8} 16$

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Solution

${log}_{8} 128 - {log}_{8} 16 = {log}_{8} \frac{128}{16}$ $[∵ {log}_{a} (\frac{M}{N}) = {log}_{a} M - {log}_{a} N]$
$= {log}_{8} 8 = 1$ $[∵ {log}_{a} a = 1]$

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