Simplify: $(m^{2} - n^{2} m)^{2} + 2 m^{3} n^{2}$

m^{2} (m^{2} + n^{4})

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

m (m^{2} - n^{4})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

m^{2} (m^{2} + n^{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(m^{2} - n^{4})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $m^{2} (m^{2} + n^{4})$
$(m^{2} - n^{2} m)^{2} + 2 m^{3} n^{2}$
$= (m^{2})^{2} - 2 (m^{2}) (n^{2} m) + (n^{2} m)^{2} + 2 m^{3} n^{2}$
$= m^{4} - 2 m^{3} n^{2} + m^{2} n^{4} + 2 m^{3} n^{2}$
$= m^{4} + m^{2} n^{4}$
$= m^{2} (m^{2} + n^{4})$

Suggest Corrections

Similar questions

(m^{2} - n^{2} m)^{2} + 2 m^{3} n^{2}

\sqrt{m^{4} n^{4}} \times \sqrt[6]{m^{2} n^{2}} \times \sqrt[3]{m^{2} n^{2}} = {(m n)}^{k}

k

(m^{2} - n^{2} m)^{2} + 2 m^{3} n^{2}

m (m^{3} - m^{2} + 1) - 2 (m^{4} - m^{3} - 1) + m^{2} (m^{2} - m + 2)

5 < n_{1} < n_{2} < n_{3} < n_{4}

n_{1} + n_{2} + n_{3} + n_{4} = 35

(n_{1}, n_{2}, n_{3}, n_{4})

Join BYJU'S Learning Program