Simplify:
$p^{2} + p - (a + 1) (a + 2)$ .

Open in App

Solution

Now,
$p^{2} + p - (3 a + 1) (3 a + 2)$
$= p^{2} + {(3 a + 2) - (3 a + 1)} p - (3 a + 1) (3 a + 2)$
$= p (p + 3 a + 2) - (3 a + 1) (p + 3 a + 2)$
$= (p + 3 a + 2) (p - 3 a - 1)$

Suggest Corrections

Similar questions

p^{2} - 3 p - (a + 1) (a - 2)

\frac{m^{8} p^{7} r^{12}}{m^{3} r^{9} p} \times p^{2} r^{3} m^{4}

\frac{1}{a + b + x} = \frac{1}{a} + \frac{1}{b} + \frac{1}{x}; a + b \neq 0

(\frac{a \sqrt{2}}{(1 + a^{2})^{- 1}} - \frac{2 \sqrt{2}}{a^{- 1}}) \frac{a^{- 3}}{1 - a^{- 2}}

p = x - y, q = y - z

r = z - r

r^{2} - p^{2} + 2 p q - q^{2}

Join BYJU'S Learning Program