Simplify:
$p^{2} + q r + p q + p r$

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Solution

$p^{2} + q r + p q + p r$

$= p^{2} + p q + q r + p r$

$= p (p + q) + r (p + q)$

$= (p + q) (p + r)$

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(p q - q r + p r) (p q + q r) - (p r + p q) (p + q - r)

p^{2} + p q + p r + q r

Question 9

In $Δ P Q R$ ,

a) PQ - QR > PR
b) PQ + QR < PR
c) PQ - QR < PR
d) PQ + PR < QR

⎡ ⎢ ⎣ \begin{matrix} - q r & p (q + r) & p r + p q p q + q r & - p r & p q + q r q r + p r & q r + p r & - p q \end{matrix} ⎤ ⎥ ⎦

| A |

Δ P Q R

∠ R > ∠ Q

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