wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Simplify:
p2qpq2pq+r2

Open in App
Solution

We have,
p2qpq2pq+r2

pq(pq)pq+r2

pq(pq1)+r2

Hence, this is the answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
x^2 - y^2
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon