wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Simplify sin3θ+sinθsinθcos2θ.

A
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
sinθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
sin2θ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2sinθ
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
2sin3θ
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is E 2sin3θ
sin3θ+sinθsinθcos2θ
=sin3θ+sinθ(1cos2θ)
=sin3θ+sinθ×sin2θ
=2sin3θ

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Trigonometric Identities_Concept
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon